3.239 \(\int \frac {1}{\sqrt {-1+x^2} \sqrt {2+4 x^2}} \, dx\)

Optimal. Leaf size=30 \[ \frac {\sqrt {1-x^2} \operatorname {EllipticF}\left (\sin ^{-1}(x),-2\right )}{\sqrt {2} \sqrt {x^2-1}} \]

[Out]

1/2*EllipticF(x,I*2^(1/2))*(-x^2+1)^(1/2)*2^(1/2)/(x^2-1)^(1/2)

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Rubi [A]  time = 0.01, antiderivative size = 30, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.095, Rules used = {421, 419} \[ \frac {\sqrt {1-x^2} F\left (\left .\sin ^{-1}(x)\right |-2\right )}{\sqrt {2} \sqrt {x^2-1}} \]

Antiderivative was successfully verified.

[In]

Int[1/(Sqrt[-1 + x^2]*Sqrt[2 + 4*x^2]),x]

[Out]

(Sqrt[1 - x^2]*EllipticF[ArcSin[x], -2])/(Sqrt[2]*Sqrt[-1 + x^2])

Rule 419

Int[1/(Sqrt[(a_) + (b_.)*(x_)^2]*Sqrt[(c_) + (d_.)*(x_)^2]), x_Symbol] :> Simp[(1*EllipticF[ArcSin[Rt[-(d/c),
2]*x], (b*c)/(a*d)])/(Sqrt[a]*Sqrt[c]*Rt[-(d/c), 2]), x] /; FreeQ[{a, b, c, d}, x] && NegQ[d/c] && GtQ[c, 0] &
& GtQ[a, 0] &&  !(NegQ[b/a] && SimplerSqrtQ[-(b/a), -(d/c)])

Rule 421

Int[1/(Sqrt[(a_) + (b_.)*(x_)^2]*Sqrt[(c_) + (d_.)*(x_)^2]), x_Symbol] :> Dist[Sqrt[1 + (d*x^2)/c]/Sqrt[c + d*
x^2], Int[1/(Sqrt[a + b*x^2]*Sqrt[1 + (d*x^2)/c]), x], x] /; FreeQ[{a, b, c, d}, x] &&  !GtQ[c, 0]

Rubi steps

\begin {align*} \int \frac {1}{\sqrt {-1+x^2} \sqrt {2+4 x^2}} \, dx &=\frac {\sqrt {1-x^2} \int \frac {1}{\sqrt {1-x^2} \sqrt {2+4 x^2}} \, dx}{\sqrt {-1+x^2}}\\ &=\frac {\sqrt {1-x^2} F\left (\left .\sin ^{-1}(x)\right |-2\right )}{\sqrt {2} \sqrt {-1+x^2}}\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 30, normalized size = 1.00 \[ \frac {\sqrt {1-x^2} \operatorname {EllipticF}\left (\sin ^{-1}(x),-2\right )}{\sqrt {2} \sqrt {x^2-1}} \]

Antiderivative was successfully verified.

[In]

Integrate[1/(Sqrt[-1 + x^2]*Sqrt[2 + 4*x^2]),x]

[Out]

(Sqrt[1 - x^2]*EllipticF[ArcSin[x], -2])/(Sqrt[2]*Sqrt[-1 + x^2])

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fricas [F]  time = 0.56, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\sqrt {4 \, x^{2} + 2} \sqrt {x^{2} - 1}}{2 \, {\left (2 \, x^{4} - x^{2} - 1\right )}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(x^2-1)^(1/2)/(4*x^2+2)^(1/2),x, algorithm="fricas")

[Out]

integral(1/2*sqrt(4*x^2 + 2)*sqrt(x^2 - 1)/(2*x^4 - x^2 - 1), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {4 \, x^{2} + 2} \sqrt {x^{2} - 1}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(x^2-1)^(1/2)/(4*x^2+2)^(1/2),x, algorithm="giac")

[Out]

integrate(1/(sqrt(4*x^2 + 2)*sqrt(x^2 - 1)), x)

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maple [A]  time = 0.04, size = 34, normalized size = 1.13 \[ -\frac {i \sqrt {-x^{2}+1}\, \EllipticF \left (i \sqrt {2}\, x , \frac {i \sqrt {2}}{2}\right )}{2 \sqrt {x^{2}-1}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^2-1)^(1/2)/(4*x^2+2)^(1/2),x)

[Out]

-1/2*I*EllipticF(I*x*2^(1/2),1/2*I*2^(1/2))*(-x^2+1)^(1/2)/(x^2-1)^(1/2)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {4 \, x^{2} + 2} \sqrt {x^{2} - 1}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(x^2-1)^(1/2)/(4*x^2+2)^(1/2),x, algorithm="maxima")

[Out]

integrate(1/(sqrt(4*x^2 + 2)*sqrt(x^2 - 1)), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.03 \[ \int \frac {1}{\sqrt {x^2-1}\,\sqrt {4\,x^2+2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((x^2 - 1)^(1/2)*(4*x^2 + 2)^(1/2)),x)

[Out]

int(1/((x^2 - 1)^(1/2)*(4*x^2 + 2)^(1/2)), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \frac {\sqrt {2} \int \frac {1}{\sqrt {x^{2} - 1} \sqrt {2 x^{2} + 1}}\, dx}{2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(x**2-1)**(1/2)/(4*x**2+2)**(1/2),x)

[Out]

sqrt(2)*Integral(1/(sqrt(x**2 - 1)*sqrt(2*x**2 + 1)), x)/2

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